Write a program to calculate pow(x,n)? 1) Given two integers x and n, you need to find x^n (given that: x and n are small and no overflow takes place)? A)Naive approach: since there is no issue of overflow, we can directly multiply x, to itself n times to get the desired result!! Code - Add caption Time Complexity: O( n ) Space Complexity: O( 1 ) The demerit of this approach is that it is more prone to overflow. As the values of x and n increases, the value of pow(x,n) becomes too large to be accommodated in int or even long long int. B)Time Optimization: The Time complexity of the naive method is O(n), which can further be improved to O(log(n)) by using a divide and conquerer approach. IDEA : if n is even : we calculate pow(x*x,n/2); else : we calculate x*pow(x*x,(n-1)/2); and we do so, till the value of n becomes == 0; By doing so, we are reducing n by factors of 2, which ultimately will give ...